/**
* Implementation of the Boyer-Moore Algorithm for pattern matching.
* @author V.Boutchkova
*/
public class BoyerMoore {
public static final int ALPHABET_SIZE = Character.MAX_VALUE + 1;
private String text;
private String pattern;
private int[] last;
private int[] match;
private int[] suffix;
public BoyerMoore(String pattern, String text) {
this.text = text;
this.pattern = pattern;
last = new int[ALPHABET_SIZE];
match = new int[pattern.length()];
suffix = new int[pattern.length()];
}
/**
* Searches the pattern in the text.
* Returns the position of the first occurrence, if found and -1 otherwise.
*/
public int match() {
// Preprocessing
computeLast();
computeMatch();
// Searching
int i = pattern.length() - 1;
int j = pattern.length() - 1;
while (i < text.length()) {
if (pattern.charAt(j) == text.charAt(i)) {
if (j == 0) {
//the left-most match is found
return i;
}
j--;
i--;
} else { //a difference
i += pattern.length() - j - 1 + Math.max(j - last[text.charAt(i)], match[j]);
j = pattern.length() - 1;
}
}
return -1;
}
/**
* Computes the function last and stores its values in the array last
.
* The function is defined as follows:
*
* last(Char ch) = the index of the right-most occurrence of the character ch * in the pattern; * -1 if ch does not occur in the pattern. ** The running time is O(pattern.length() + |Alphabet|). */ private void computeLast() { for (int k = 0; k < last.length; k++) { last[k] = -1; } for (int j = pattern.length()-1; j >= 0; j--) { if (last[pattern.charAt(j)] < 0) { last[pattern.charAt(j)] = j; } } } /** * Computes the function match and stores its values in the array
match
.
* The function is defined as follows:
* * match(j) = min{ s | 0 < s <= j && p[j-s]!=p[j] * && p[j-s+1]..p[m-s-1] is suffix of p[j+1]..p[m-1] }, * if such s exists, else * min{ s | j+1 <= s <= m * && p[0]..p[m-s-1] is suffix of p[j+1]..p[m-1] }, * if such s exists, * m, otherwise, * where m is the pattern's length and p is the pattern. ** The running time is O(pattern.length()). */ private void computeMatch() { /* Phase 1 */ for (int j = 0; j < match.length; j++) { match[j] = match.length; } //O(m) computeSuffix(); //O(m) /* Phase 2 */ //Uses an auxiliary array, backwards version of the KMP failure function. //suffix[i] = the smallest j > i s.t. p[j..m-1] is a prefix of p[i..m-1], //if there is no such j, suffix[i] = m //Compute the smallest shift s, such that 0 < s <= j and //p[j-s]!=p[j] and p[j-s+1..m-s-1] is suffix of p[j+1..m-1] or j == m-1}, // if such s exists, for (int i = 0; i < match.length - 1; i++) { int j = suffix[i + 1] - 1; // suffix[i+1] <= suffix[i] + 1 if (suffix[i] > j) { // therefore pattern[i] != pattern[j] match[j] = j - i; } else {// j == suffix[i] match[j] = Math.min(j - i + match[i], match[j]); } } //End of Phase 2 /* Phase 3 */ //Uses the suffix array to compute each shift s such that //p[0..m-s-1] is a suffix of p[j+1..m-1] with j < s < m //and stores the minimum of this shift and the previously computed one. if (suffix[0] < pattern.length()) { for (int j = suffix[0] - 1; j >= 0; j--) { if (suffix[0] < match[j]) { match[j] = suffix[0]; } } int j = suffix[0]; for (int k = suffix[j]; k < pattern.length(); k = suffix[k]) { while (j < k) { if (match[j] > k) match[j] = k; j++; } } }//endif } /** * Computes the values of
suffix
, which is an auxiliary array,
* backwards version of the KMP failure function.
* suffix
is O(m).
*/
private void computeSuffix() {
suffix[suffix.length-1] = suffix.length;
int j = suffix.length - 1;
//suffix[i] = m - the length of the longest prefix of p[i..m-1]
for (int i = suffix.length - 2; i >= 0; i--) {
while (j < suffix.length - 1 && pattern.charAt(j) != pattern.charAt(i)) {
j = suffix[j + 1] - 1;
}
if (pattern.charAt(j) == pattern.charAt(i)) { j--; }
suffix[i] = j + 1;
}
}
}